Teamturnier Vorrunde - Gruppe 1 - Böblingen - 21.12.2015

1
Nord / -
AD98
K10
1092
A542
10
A76432
43
B1076
N
1
B6542
985
AD85
8
N/S 2 +1
K73
DB
KB76
KD93
SA
N4432
S4432
O1
W1
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
−22,0−111N 3SA -28      1001021122,0
20,0113N 3SA +14430      104−11−20,0
24,0112N 3SA +36490      101−11−24,0
−22,0−114N 4 -25      1001031122,0
2
Ost / NS
AD952
K
AK7
AB74
863
732
D862
952
2O
B10
D1084
B10543
K10
N/S 6SA =
K74
AB965
9
D863
SA
N62566
S62466
O
W
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
13,001N 6 =B1430      1020−13,0
13,0133N 6 =B1430      104−13−13,0
13,002N 6 =B1430      1010−13,0
−39,0−134N 4 +2B680      1031339,0
3
Süd / OW
K10974
543
652
B7
AD53
1086
D7
AK43
3
S
862
AK2
AK104
1052
O/W 4 =
B
DB97
B983
D986
SA
N
S
O43343
W43343
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
2,001W 3SA =10      6001020−2,0
2,023W 3SA =7      600104−2−2,0
2,002W 3SA =10      6001010−2,0
−6,0−24W 3SA +27      66010326,0
4
West / alle
KB986
B97
A74
53
105
D65
6
AK107642
W4
D432
10843
B982
9
N/S 3SA +1
A7
AK2
KD1053
DB8
SA
N14344
S14344
O
W
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
22,0−11S 3SA +14630      1021−22,0
−30,0−53S 3SA -1A      100104530,0
25,012S 3SA +2K660      101−1−25,0
−17,054S 3 =A110      103−517,0
5
Nord / NS
1087
B83
A8
KB874
ADB9543
74
B103
10
N
5
K62
D102
K952
652
O/W 6 X -4
AK965
D764
AD93
SA
N626
S626
O2
W2
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
11,011N 4 =10620      102−1−11,0
−34,0−123W 3 -1350      1041234,0
8,0−12S 5 =A600      1011−8,0
15,0124S 5 =10650      103−12−15,0
6
Ost / OW
ADB10962
K
76
A76
8753
A1083
D
10854
6O
DB52
AB109843
D9
O/W 5 X -1
K4
9764
K52
KB32
SA
N142
S142
O43
W43
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
7,062N 4 +1A450      103−6−7,0
7,014N 4 +1A450      101−1−7,0
4,0−11N 4 =2420      1041−4,0
−18,0−63O 5 -2A200      102618,0
7
Süd / alle
842
KD9
K3
AB762
106
65
DB109874
KD
7
S
K953
AB743
A2
98
O/W 3 =
ADB7
1082
65
10543
SA
N32
S21
O31
W31
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
−35,0−112O 3SA =6      6001031135,0
16,0−14O 3 -16100      1011−16,0
19,011N 3 +1A130      104−1−19,0
0,0113S 3 -1K      100102−110,0
8
West / -
54
K73
B8643
654
AB86
A4
D109
A1087
W8
D2
D109862
K
D932
O/W 4 =
K10973
B5
A752
KB
SA
N1
S1
O4411
W441
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
−11,0−112O 4 =A      4201031111,0
−11,004O 4 =10      420101011,0
−11,001W 4 =5      420104011,0
33,0113W 3SA -34150      102−11−33,0
9
Nord / OW
DB854
AD8
B75
94
A932
K965
93
752
N
9
7
B4
AKD1084
KB106
N/S 2 +1
K106
10732
62
AD83
SA
N13
S13
O121
W121
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
4,022N 3 -1A      50103−2−4,0
−4,0−24O 3 =10      11010124,0
4,021N 3 -1A      50104−2−4,0
−4,0−23O 3 =6      11010224,0
10
Ost / alle
1098
109843
87
975
4
KB5
AB54
KDB102
10O
D765
AD62
D102
A4
O/W 6 =
AKB32
7
K963
863
SA
N
S
O65525
W64522
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
1,012O 4 +1A      650103−1−1,0
3,014O 5 +22      640101−1−3,0
0,0−11O 3SA +23      66010410,0
−4,0−13O 3SA +3A      69010214,0
11
Süd / -
A2
8652
A109654
4
10873
1043
K7
B1085
11
S
K54
KDB9
B82
A92
N/S 2 +1
DB96
A7
D3
KD763
SA
N13111
S13111
O
W
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
7,011N 2 +1K110      103−1−7,0
4,052N 1SA =K90      104−5−4,0
4,0−13N 2 =K90      1011−4,0
−15,0−54S 2SA -2K      100102515,0
12
West / NS
K8754
762
4
D764
AB
93
K9765
K1053
W12
92
AB108
ADB103
A9
O/W 3SA =
O/W 5 =
D1063
KD54
82
B82
SA
N
S
O2523
W2523
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
1,0111W 3SA =5      400103−11−1,0
1,0−102W 3SA =4      40010410−1,0
−36,0−113W 6 =6      9201011136,0
34,0104W 6 -1550      102−10−34,0
13
Nord / alle
B4
AKD63
K1072
86
KD83
842
A
DB542
N
13
75
B109
DB986
A107
N/S 1SA +1
A10962
75
543
K93
SA
N1222
S1222
O1
W1
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
9,011N 2 +110140      103−1−9,0
9,082N 2 +1D140      104−8−9,0
5,0−13S 2 =A110      1011−5,0
−23,0−84S 3SA -24      200102823,0
14
Ost / -
AD765
98
B
A10832
109
D106
K1095
B954
14O
KB4
KB73
D7432
K
O/W 4 X -1
832
A542
A86
D76
SA
N231
S231
O31
W31
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
5,001N 3 =2140      1030−5,0
−15,0−52N 4 -1K      50104515,0
5,003N 2 +1K140      1010−5,0
5,054N 3 =2140      102−5−5,0
15
Süd / NS
B109752
AD854
D
8
D8
9732
765
B942
15
S
64
B
AKB92
AD653
O/W 6 X -3
AK3
K106
10843
K107
SA
N553
S553
O32
W32
Paar IMPImpsNSKontraktAussp.ErgebnisOWImpsPaar IMP
−20,0−101N 2 +3A200      1031020,0
20,0102N 4 +1A650      104−10−20,0
20,0103N 5 =A650      101−10−20,0
−20,0−104N 2 +3A200      1021020,0